GasSavers_bobski |
04-24-2009 05:11 AM |
You could replace the brake light relay with a diode.
Assuming your brake light circuit is a positive switched design (one side of each bulb grounded, with switched power on the other), the wire between the switch and bulbs always sees 12V+ or ground. It gets 12V+ when the switch is activated thanks to the resistance of the bulb filaments. It sees ground when the switch is off because the unlit bulb filaments have a relatively low resistance, so small-ish currents (such as those that flow through a relay coil) fed to the bulb-switch wire can drain to ground through the bulbs without lighting them. In your design, these are the same conditions seen on the wire connecting the two relays.
The only consequence of connecting that wire directly to the brake light circuit is that stepping on the brakes would cause power to flow back through your relay coil (the ground path being the lockup solenoid), energizing it and either latching it or maybe causing it to cycle on/off (it would sound like a buzzer) as the relay contacts make and break.
To avoid that, you need a diode (a 1N4001 should do nicely and be easy to find) on the wire between your relay and the brake circuit, banded side towards the brake circuit. That will allow current to flow only from the relay to the brake circuit (when the circuit wire is grounded / lights are off), or not at all (when the circuit wire has 12V+ / lights are on).
|